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Whenever we have 366 days in a year instead of 365 days, that year is called a leap year. Leap year comes every fourth year. This adjusts the calendar year with the solar year.

In this tutorial, we will learn to write a C program to check whether a given year is a leap year or not.

Problem Statement:

Write a C program to check whether a year is a leap year or not.

Here our program will take integer input from the user.

It should print if the result on the screen. We will be using if-else statement to make this program.

Program

#include <stdio.h>
int main()
{
    int year;
    printf("Enter a year: ");
    scanf("%d", &year);
    if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
        printf("%d is a leap year", year);
    else
        printf("%d is not a leap year", year);
    return 0;
}

 Example:

Input 1: 2000

Output:

2000 is a leap year

Input 2: 2001

Output:

2001 is not a leap year

Program Explanation:

• We have included stdio.h to enable the program to do input and output operations.
• The main() function is the entry point of any C program.
• Here, we have declared the variable ‘year’ of integer type to store user input.
• printf() function is used to show the output/message on the display.
• scanf() function is used to read the input year given by the user.
• if-else statement is used to apply check whether the given year is divisible by 4 and 100.
• The return statement returns 0 to the operating system and denotes the end of a program.

Conclusion:

In this blog, we have written a C program to check whether a year is a leap year or not using the if-else statement.

The above program takes a integer as input from the user.

And After taking input, with the help of if else statement it checks whether the number is divisible by 4 and 100 or divisble by 400.

I hope this blog was helpful to you in understanding the C program.