In this tutorial, you will learn Writing C Program to Find the sum of all prime numbers between 1 to n using a while loop conditional statement. We will also see the algorithm, examples, and programming explanations for your better understanding.
Required Knowledge
- C Programming Basics
- C Programming Operators
- C printf and Scanf
- While loop in C
Problem Statement
We have to Write a C program that will take the number n as input. And after taking the input Find the all prime numbers between 1 and n using a while loop and then sum them. For a better understanding, you can refer to the below example which will help you to understand what you have to achieve.
Example
Input:
Enter the value of n: 10
Output:
The sum of prime numbers between 1 and 10 is: 17
In the above example, you can see the input is 10. The prime number between 1 to 10 are 2, 3, 5, 7, and the sum of these prime numbers are 17.
Algorithm
- Start the program.
- Declare the variables
n,num,isPrime, andsum. - Read the value of
nfrom the user. - Initialize
numto 2 andsumto 0. - Enter the outer while loop with the condition
num <= n.- Initialize
isPrimeto 1 (true). - Declare the variable
divisorand initialize it to 2. - Enter the inner while loop with the condition
divisor <= sqrt(num).- Check if
numis divisible bydivisorwithout a remainder.- If true, set
isPrimeto 0 (false) and break out of the loop. - If false, continue to the next iteration.
- If true, set
- Increment
divisorby 1.
- Check if
- Exit the inner while loop.
- Check the value of
isPrime.- If
isPrimeis 1, addnumtosum. - If
isPrimeis 0, continue to the next iteration.
- If
- Increment
numby 1.
- Initialize
- Exit the outer while loop.
- Print the sum of prime numbers as: “The sum of prime numbers between 1 and n is: sum”.
- End the program
Program to find sum of all prime numbers between 1 to n
#include <stdio.h>
#include <math.h>
int main() {
int n, num = 2, isPrime, sum = 0;
printf("Enter the value of n: ");
scanf("%d", &n);
while (num <= n) {
isPrime = 1;
int divisor = 2;
while (divisor <= sqrt(num)) {
if (num % divisor == 0) {
isPrime = 0;
break;
}
divisor++;
}
if (isPrime == 1) {
sum += num;
}
num++;
}
printf("The sum of prime numbers between 1 and %d is: %d\n", n, sum);
return 0;
}
Output
Enter the value of n: 12
The sum of prime numbers between 1 and 12 is: 28
Program Explanation
- The program takes input for the value of n from the user.
- It initializes a variable
numto 2, which represents the first number to be checked for primality. - It initializes a variable
sumto 0, which will hold the running sum of prime numbers. - The program enters a while loop with the condition
num <= nto iterate through numbers from 2 to n. - Inside the while loop, it checks if
numis a prime number. - It initializes a variable
isPrimeto 1, which represents the initial assumption thatnumis prime. - It initializes a variable
divisorto 2, which will be used to check divisibility. - It enters another while loop with the condition
divisor <= num/2to check ifnumis divisible by any number other than 1 and itself. - Inside the inner while loop, it checks if
numis divisible by the current value ofdivisor. - If
numis divisible, it sets the value ofisPrimeto 0 and breaks out of the inner while loop. - It then increments the value of
divisorby 1 to move on to the next possible divisor. - The inner while loop continues until
divisorexceeds half ofnum. - After the inner while loop, it checks the value of
isPrime. - If
isPrimeis 1, it adds the value ofnumtosum. - It then increments the value of
numby 1 to move on to the next number. - The outer while loop continues until
numexceeds the value of n. - Once the while loop is complete, the program prints the value of
sum, which represents the sum of all prime numbers between 1 and n. - The program ends.
Conclusion
The C program successfully finds the sum of all prime numbers between 1 and n using a while loop. By iterating through the numbers and checking each number for primality using a nested while loop, it accumulates the prime numbers and calculates their sum. The program then displays the sum on the screen.





